von Dr. Tiziana Masullo
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[1.] Tim/Fragment 069 25 - Diskussion Zuletzt bearbeitet: 2014-11-27 22:14:48 Hindemith | Copper 2010, Fragment, Gesichtet, SMWFragment, Schutzlevel sysop, Tim, Verschleierung |
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Untersuchte Arbeit: Seite: 69, Zeilen: 25-32 |
Quelle: Copper 2010 Seite(n): 1 (online source), Zeilen: - |
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Copper is one of the two exceptions to the writing of electron configurations. One would expect copper to be an s2d9 ion. Instead, one electron is borrowed from the 4s orbital to completely fill the 3d orbital. Copper metal is therefore paramagnetic due to the unpaired electron in the orbital [sic]. The two most common ions formed by copper are the +1 (cuprous) and +2 (cupric). The cuprous ion is the less stable of the two oxidation states and is easily oxidized. Since electrons are lost first out of the 4s orbital, the electron configuration of the cuprous ion is 4s03d10 and is therefore diamagnetic while the cupric ion is paramagnetic (4s03d9). | Copper is one of the two exceptions to the writing of electron configurations. One would expect copper to be an s2d9 ion. Instead, one electron is "borrowed" from the 4s orbital to completely fill the 3d orbitals. Copper metal is therefore paramagnetic due to the unpaired electron in the 4s orbital. [...]
[...] The two most common ions formed by copper are the +1 (cuprous) and +2 (cupric).The cuprous ion is the less stable of the two oxidation states and is easily oxidized. Therefore, any work done with copper(I) compounds must be carried out in an inert atmosphere. Since electrons are lost first out of the 4s orbital, the electron configuration of the cuprous ion is 4s03d10 and the [sic] it is therefore diamagnetic. [...] [...] Removal of a second electron results in the a 4s03d9 configuration. Therefore the cupric ion is paramagnetic. |
The source is not mentioned. |
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